Nuprl Lemma : spread_to_pi12
9,38
postcript
pdf
A
:Type,
B
:(
A
Type),
p
:(
x
:
A
B
(
x
)),
C
:Type,
b
:(
x
:
A
B
(
x
)
C
).
let
x
,
y
=
p
in
b
(
x
,
y
) =
b
(
p
.1,
p
.2)
latex
ProofTree
Definitions
t
T
,
x
(
s
)
,
x
:
A
.
B
(
x
)
,
t
.2
,
t
.1
,
x
(
s1
,
s2
)
origin
A:Type, B:(A
Type), p:(x:A 
B(x)), C:Type, b:(x:AB(x)C).
A:Type, B:(AType), p:(x:A B(x)), C:Type, b:(x:AB(x)C).
Tx:A. B(x)